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x^2=6x/3
We move all terms to the left:
x^2-(6x/3)=0
We add all the numbers together, and all the variables
x^2-(+6x/3)=0
We get rid of parentheses
x^2-6x/3=0
We multiply all the terms by the denominator
x^2*3-6x=0
Wy multiply elements
3x^2-6x=0
a = 3; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·3·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*3}=\frac{12}{6} =2 $
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